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Network Theory: 4 Ohm Resistor with 12 Ohm Capacitor and 50 V Source

10:05 Edit
Statement: A 4 Ohm Resistor connects in series with a Capacitive whose impedance is given by 12 ohms. The power Source is a 50 VAC. Find the Power Dissipated by the circuit.

4-ohm-resistor-with-12-ohm-capacitor-and-50-v-source
Correct answer: 62.5 W.
Solution Steps:
  1. Find overall impedance which is 4 - 12j
  2. Now apply the formula of Power which is P = V2/R
  3. After conversions and division, we achieve the final answer: 62.5 + 187.5j
  4. 62.5 provides the power dissipated in the circuit.
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5 comments:

  1. Unknown15 April 2017 at 04:06

    sir how -12j comes ?plz guide me?

    ReplyDelete
    Replies
    1. Electrical Engineering16 April 2017 at 00:30

      With capacitor we always use the negative symbol and a j which represents reactance. For AC Components (Capacitor and Inductor) we always have to include this symbol 'j'.
      If it was an inductor with 12 we should have used +12j instead. Hope you got it.

      Delete
    2. Unknown16 April 2017 at 08:02

      yeah sir got it but why we used negative sign for capacitor n +ive for inductor

      Delete
  2. Unknown15 April 2017 at 08:25

    I got the 62.5 value but the imaginary part is pretty confusing... Supposed to be + since its a capacitor...

    ReplyDelete
    Replies
    1. Electrical Engineering16 April 2017 at 00:32

      Capacitor always uses negative sign dear, now when it is in denominator it used the negative sign, but when it goes in numerator it changes its sign.

      Delete

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